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USB Battery Pack - 1800 mAh
Power on the go? Why didn't you ask? We've got plenty! These portable, rechargeable lithium-polymer battery packs are simple, compact and make for a great way to power your widgets in the field. Best of all, they're dead simple to operate: Just connect your device to the USB-A port on the battery pack and press the power button. An LED will alert you to the charge level of the battery and start powering your device. The battery pack will turn off on its own when your device stops drawing power from it. To recharge the battery pack, just plug it into your computer or phone charger using a USB micro-b cable.
This particular battery pack has an 1800mAh capacity and will source 700mA at 5.5VDC.
Note: Our latest shipment of these actually have an 1800mAh battery instead of a 2000mAh.
Note: Due to shipping restrictions, only two batteries can be shipped together at one time. We should be able to ship more than two batteries at a time by the end of 2014.
- 13.5 x 54.2 x 95mm
- Charging IC Datasheet
- [MSDS](http://cdn.sparkfun.com/datasheets/Prototyping/Lithium Ion Battery MSDS.pdf)
USB Battery Pack - 1800 mAh Product Help and Resources
Core Skill: Electrical Prototyping
If it requires power, you need to know how much, what all the pins do, and how to hook it up. You may need to reference datasheets, schematics, and know the ins and outs of electronics.
Skill Level: Noob - You don't need to reference a datasheet, but you will need to know basic power requirements.
See all skill levels
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Customer Reviews
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Could someone explain to me why it's cheaper to buy this than just the battery alone? I could save $2 by buying one of these and taking the battery out. Seems silly to me, unless I'm missing something.
The arduino doesn't have enough load to keep the battery on. Add a led or resistor to increase the load on the battery. Watch the video, this is explained..
Does anyone know the minimum current draw to keep the battery on? I'm using it to power some LEDs and I don't think they are pulling enough current to keep the battery on-- it shuts off after 10 seconds or so.
Details please. How long will it source 700mA at 5.5VDC? Battery is 2000mAh, but which voltage?
From charger datasheet, we can infer its a single cell. Output is 5.5v, so we can infer it has a boost circuit. Where is the datasheet? What is the efficiency of said circuit?
Because I'd prefer a "1000mAh battery pack with 90% efficient boost circuit" over a "2000mAh with 40% efficient boost", even if it looks less beefy...
To potential customers... do not assume this will give you 2 * 3.7/(0.7 * 5.5)=1.9 hours while draining 700mA.
You can easily assume:
Li-Ion battery, nominal 3.7V (that's what they're typically these days.)
90% efficient boost circuit. (maybe 88%? Maybe 92%? but that's a minor difference.)
So 2000mA(3.7/5.5).9 = 1.210Ah. NOTICE: That 2000mAh is on an excessive discharge. typically, you never want to run below 20%, and 30% would be even better, to ensure longterm usability. It's less important with a 1Cell device, but still important. So consider further derating this.
Regards :).