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August 14, 2011
Product BOB-09964 |
about 2 years ago
Looking at the schematic, I see R1 and C1 forming a high pass filter, followed by C3 and R5 forming a low pass filter. The general equation for RC filter corner frequencies is
3db corner freq in hz = 1/(2 * Pi * R in ohms * C in farads)
I calculate (better check my math!)
high pass = 1/(6.28 * 2.210^+3 * 4.710^-6) = 15.4 Hz
That sounds reasonable unless you want infrasound.
low pass = 1/(6.28 * 1010^+3 * 1210^-12) = 1,300,000 Hz
That sounds a little high to me for audio!
If they used C3=12 nanofarads instead of picofarads
the low pass would have been 1,300 Hz, which is in the audio ballpark.
I wonder if there is a typo in the schematic, or if the
circuit is incorrect? Again, better check my analysis!
No public wish lists :(