Member Since: January 11, 2006

Country: United States

  • Well said :)

    Someone asked me how I came up with the idea. After some thought, I realized it all started because I didn't have a spare key.

  • Lol ... That's a lot of people's first comments. It won't read any gestures when the screen of the Android phone is off. I don't have to unlock it, just hit the power button and shake. It automatically turns the screen off in five seconds.

  • Darn ... needed this exact product with an I2C or 1-Wire interface.

  • Amazing, I saw this in the new products list and the balloon grabber in the video was the EXACT purpose I had in mind for it when I clicked!

  • I'd be very interested to know the temperature range of this module. The datasheet does not give a temp range.
    I've heard there might be problems in cold weather, but I'd like to use it outdoors.

  • This is as logical as saying Wal-Mart should not have Black Friday sales. Obviously, not everyone will get the PlayStation for $50 and the gum off the bottom of their shoe.
    It was advertised very accurately as to exactly what the deal was. There is no foul play here - it was your fault as much as anyone else's that you didn't get the sale.
    Just think, you've got a whole year to let the bitterness subside and try again ;)

  • I also use Octave. It's got a pretty healthy support community, and is very compatible with Matlab code.
    I've used Octave for most of my Matlab assignments throughout college without any significant issues - while it doesn't have the same external hardware interfacing and other features of Matlab, it's still very powerful.
    It also outputs things nicely using gnuplot, without requiring you to know all the funky syntax.

  • I believe the issue that most of you are having is that you are neglecting to take into account the ~3V drop of the LM335 into account. It is a diode, which needs to be included in the resistor calculation.
    Ohm's law: V = IR. But if you're running on 5V, don't use V = 5V! The diode blocks ~3V, so V = (5V - 3V) = 2V.
    Solving for R where V = 2V and I = 1mA (R = V/I = 2V/.001A), you should find that a 2Kohm resistor at 5V is appropriate.
    Best of luck.

  • Yeah, I think you had a pretty good approach - I set the date I was gonna do it, then didn't sleep for about three nights leading up to it trying to get it programmed up and the bugs kicked out. No wonder I forgot to change the batteries ;)

  • Very nice work, Robert. Excellent geek form. And congratulations!
    This is similar to what I did with to propose using some of my first SparkFun parts. No GPS or RFID - it had the knockoff Nokia LCD screen, a VS1002D MP3 chip, and an SD card in a Radio Shack enclosure with some arrow buttons all tied into an ATMega128.
    My girlfriend (wife-to-be) had to follow the audio-visual clues loaded from the SD card, including recordings of me telling her clues drenched in sweet nothings, set to our favorite songs, and use the buttons to punch in a retrieved code to get the next clue.
    With each clue, she got something like shoes, earrings, a dress, a hairdo, necklace, etc., and the last clue she ended up in my garage which was decked out prom style with me in a tux.
    Fortunately, her driver had the backup plan - Batteries weren't fresh when I gave it to her, and it died about half way through. Don't worry - she still got the ring!
    It's almost five years later, I'm sure she's forgotten that I screwed up the batteries... ;)

No public wish lists :(