February 2, 2009
Tutorial - Controllable Power Outlet
about 6 years ago
However, thinking at the CE of the transistor too, the voltage at the resistor will be U<3V, so R will be <150 Ohm, not 1k!
Oh, sorry the resistor is not grounded as i see…
Supposing the LED needs 2V, it remains for the series resistor 3V, we know that the LED needs 20mA (0.02A); using Ohm’s law results R=U/I=3/0.02=150 Ohm for the series resistor. I don’t understand how did you get 1K for it?! Maybe a mistake?
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