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Member #599487

Member Since: September 25, 2014

Country: United States

  • The little drawings are confusing, but it kind of makes sense if you think about them for an always-on LED. Remember that you're never actually connecting directly to both positive and ground of your voltage source -- that would just be a short! You're usually interrupting the positive line to a device.

    Think about the pinout this way:

    • ground -- this is ground for the LED. Attach a resistor between this and ground (2.2k is nice and conservative on a 12v source, should give you ~5mA).
    • plus -- this is the positive-out to your device. It will only be on when the switch is on.
    • lamp -- weird choice of icon, but this is the positive-in; connect it to the positive terminal of your voltage source.

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