Thermal Gap Filler

This Thermal Gap Filler provides 1.1W/mK of thermal conductivity that can conform to most surfaces. It’s perfect for high-value products that you need to keep cool, as it is a poor conductor of electricity while remaining a great conductor of heat! No additional adhesive is required when applying the Thermal Gap Filler, as it is naturally tacky and sticks to whatever you need it to — just be sure that’s where you need it!

This gap filler is what we use on our Stepoko motion controller as well as what we recommend to use with our ESP32 Thing Power Control Shield, as it is both electrically insulating and stable from -40°C to 160°C while meeting a UL 94 VO rating.

  • Soft and compressible for low-stress applications
  • Naturally tacky, needing no further adhesive coating
  • 1.1 W/mK thermal conductivity
  • Comes in 9"x9" sheets

Thermal Gap Filler Product Help and Resources

Core Skill: Robotics

This skill concerns mechanical and robotics knowledge. You may need to know how mechanical parts interact, how motors work, or how to use motor drivers and controllers.

1 Robotics

Skill Level: Noob - You will be required to put together a robotics kit. Necessary parts are included and steps will be easy to follow. You also might encounter basic robotics components like bearings, mounts, or other hardware and need a general idea of how it goes together.
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Core Skill: DIY

Whether it's for assembling a kit, hacking an enclosure, or creating your own parts; the DIY skill is all about knowing how to use tools and the techniques associated with them.

1 DIY

Skill Level: Noob - Basic assembly is required. You may need to provide your own basic tools like a screwdriver, hammer or scissors. Power tools or custom parts are not required. Instructions will be included and easy to follow. Sewing may be required, but only with included patterns.
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Customer Comments

  • 1.1 W/mK

    That’s presumably watts per meter kelvin, not watts per millikelvin, for anybody who’s not familiar with the specs for this kind of material.

    My understanding of it, which could well be incorrect, is that you divide the contact area in m2 by the thickness in m to get the length value for use in thermal conductivity calculations. For example, if you have a 10 cm square, that’s (0.1 m)2 = 0.01 m2. Then divide that by the thickness, 0.00102 m, to get 9.8 m. Then if you have a temperature difference of 15 K (15 °C), it’s 15 K * 9.8 m * 1.1 W/(m*K) = 161 W.

  • The link to the motion controller in the description just sends you right back to this product…

  • Which thickness is this material? The data sheet lists values in the range of 0.02" to 0.10". Thanks!

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